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How do you simplify #cosx(2sinx + cosx)-sin^2x#?

1 Answer

Feb 16, 2015

You can start by multiplying #cos(x)# to get:

#2sin(x)cos(x)+cos^2(x)-sin^2(x)=# or:

#=[2sin(x)cos(x)]+[cos^2(x)-sin^2(x)]=#

which can be written as:

#=sin(2x)+cos(2x)#

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