Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you simplify # (y²-25) / (3y-7)#?

1 Answer

Nov 7, 2015

#(y^2-25)/(3y-7)=((y+5)(y-5))/(3y-7)#

Explanation:

#(y^2-25)/(3y-7)#

Rewrite #25# as #5^2#.

#(y^2-5^2)/(3y-7)#

#(y^2-5^2)# is an example of the difference of squares, #a^2-b^2=(a+b)(a-b)#, where #a=y and b=5#.

#((y+5)(y-5))/(3y-7)#

Related questions

See all questions in Division of Polynomials

Impact of this question

1436 views around the world

You can reuse this answer
Creative Commons License