How do you simplify $- y^{2} (3 y - 5)$ $-y^2(3y-5)$ ?

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Answer 1 · 2015-10-10T05:19:08

$- y^{2} (3 y - 5) = - 3 y^{3} + 5 y^{2}$ $-y^2(3y-5)=color(green)(-3y^3 + 5y^2$

$a \cdot (b - c) = a \cdot b - a \cdot c$ $color(blue)(a*(b-c) = a*b - a*c$ ---- (Distributive Property)

Applying it to the given expression,
$- y^{2} (3 y - 5) = - y^{2} (3 y) - (- y^{2}) (5)$ $-y^2(3y-5) = -y^2(3y) - (-y^2)(5)$

We also know that $a^{m} \cdot a^{n} = a^{m + n}$ $color(blue)(a^m*a^n = a^(m+n)$

Hence the expression will be:

$- 3 y^{2 + 1} + 5 y^{2}$ $-3y^(2+1) + 5y^2$

$= - 3 y^{3} + 5 y^{2}$ $=color(green)(-3y^3 + 5y^2$

How do you simplify -y^2(3y-5)−y2(3y−5)-y^2(3y-5)?