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How do you simplify #(x^(2/9))^(3/8)#?

1 Answer

Oct 23, 2016

#x^(1/12)" "or" "root12(x)#

Explanation:

Recall: one of the laws of indices:

#(x^m)^n = x^(mxxn)#

Raising a power to a power, multiply the indices.

#(x^(2/9))^(3/8) = x^((2xx3)/(9xx8))" "larr (cancel2xxcancel3)/(cancel9^3xxcancel8^4) = 1/12#

=#x^(1/12)#

This can also be written as #root12(x)#

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