How do you simplify $(x^2+2x-35)/ (x^2+4x-21) * (x^2+3x-18)/(x^2+9x+18)$ ?

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Answer 1 · 2015-07-25T22:22:11

Simplify quadratic expression f(x)

Ans: $(x - 5)/(x + 3)$

First factor all the trinomials:
$(x^2 + 2x - 35) = (x - 5)(x + 7)$ ; $(x^2 + 3x - 18) = (x - 3)(x + 6)$

$(x^2 + 4x - 21) = (x + 7)(x - 3)$ ; $(x^2 + 9x + 18) = (x + 3)(x + 6)$

$f(x) = ((x - 5)(x + 7))/((x + 7)(x - 3)).((x - 3)(x +6))/((x + 3)(x + 6))$ =

$= (x - 5)/(x + 3)$

How do you simplify (x^2+2x-35)/ (x^2+4x-21) * (x^2+3x-18)/(x^2+9x+18)(x^2+2x-35)/ (x^2+4x-21) * (x^2+3x-18)/(x^2+9x+18)?