How do you simplify $\frac{w^{3} - 27}{4 w^{2} - 5 w - 21}$ $(w^3-27)/(4w^2-5w-21)$ ?

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Answer 1 · 2017-02-03T04:29:14

Factorizing the fraction we get

$\frac{w^{3} - 27}{4 w^{2} - 5 w - 21}$ $(w^3-27)/(4w^2-5w-21)$

$\frac{(w - 3) (w^{2} + 3 w + 9)}{(w - 3) (4 w + 7)}$ $((w - 3) (w^2 + 3 w + 9))/((w - 3) (4 w + 7))$

$((cancel(w - 3) )(w^2 + 3 w + 9))/((cancel(w - 3)) (4 w + 7))$

$(w^2 + 3 w + 9)/(4 w + 7)$

How do you simplify (w^3-27)/(4w^2-5w-21)w3−274w2−5w−21(w^3-27)/(4w^2-5w-21)?