How do you simplify the Square root of 48? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer MeneerNask Jul 23, 2015 In cases like this you factorise the #48# and see if you can find any squares to be taken out from under the root. Explanation: #48=16*3=4^2*3-># #sqrt48=sqrt(4^2*3)=sqrt(4^2)*sqrt3=4sqrt3# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 18980 views around the world You can reuse this answer Creative Commons License