How do you simplify the factorial expression ((n+1)!)/(n!)(n+1)!n!?

1 Answer
Feb 18, 2017

n+1n+1

Explanation:

(n+1)! = (n+1) * n * (n-1 )* (n-2)* ... 2*1

n! = n * (n-1 )* (n-2)* ... 2*1

:. ((n=1)!)/(n!) = ((n+1) * cancel( n * (n-1 )* (n-2)* ... 2*1))/cancel( n * (n-1 )* (n-2)* ... 2*1)

=n+1