How do you simplify the factorial expression $(10!)/(8!)$ ?

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Answer 1 · 2017-02-07T06:55:22

$90.$

Recall that, $(n!)=n(n-1)(n-2)...3xx2xx1,$

$=n{(n-1)(n-2)(n-3)...3xx2xx1}$

$rArr (n!)=n{(n-1)!}...............(ast)$

$:. (10!)/(8!)={10(9!)}/(8!), ...............[because, (ast)]$

$=[(10){9(cancel(8!))}]/cancel(8!)$

$=(10)(9)$

$=90.$

How do you simplify the factorial expression (10!)/(8!)(10!)/(8!)?