How do you simplify the expression #[(z^-2)^2]^3# using the properties?

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Answer 1 · 2018-02-02T23:03:15

#1/z^12#

First, #z^-n=1/z^n#

So it becomes #[1/z^(2^2)]^3#

Becuase #1^n=1# and #(a/b)^n=a^n/b^n#

And #(a^b)^c=a^(bc)# Makes the equation

#[1/z^4]^3#

Using the last three again, we get

#1/z^12#