Which exponential property do you use first to simplify $\frac{(2 a^{2} b c^{2}) (6 a b c^{3})}{4 a b^{2} c}$ $\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}$ ?

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Which exponential property do you use first to simplify $\frac{(2 a^{2} b c^{2}) (6 a b c^{3})}{4 a b^{2} c}$ $\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}$ ?

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Answer 1 · 2014-11-05T10:38:34

I would use the exponential property

$b^{x} \cdot b^{y} = b^{x + y}$ $b^x cdot b^y=b^{x+y}$

to simplify the numerator first.

$\frac{(2 a^{2} b c^{2}) (6 a b c^{3})}{4 a b^{2} c} = \frac{12 a^{3} b^{2} c^{5}}{4 a b^{2} c}$ ${(2a^2bc^2)(6abc^3)}/{4ab^2c}={12a^3b^2c^5}/{4ab^2c}$

I hope that this was helpful.

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Which exponential property do you use first to simplify $\frac{(2 a^{2} b c^{2}) (6 a b c^{3})}{4 a b^{2} c}$ $\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}$ ?

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Which exponential property do you use first to simplify \frac{(2a^2bc^2)(6abc^3)}{4ab^2c}(2a2bc2)(6abc3)4ab2c\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}?

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Which exponential property do you use first to simplify $\frac{(2 a^{2} b c^{2}) (6 a b c^{3})}{4 a b^{2} c}$ $\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}$ ?