How do you simplify $\frac{t^{2} - 4 t - 32}{t - 8} ?$ $(t^2-4t-32)/(t-8)?$ ?

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Answer 1 · 2018-05-11T01:38:13

$t + 4$ $t+4$

Let's factor the numerator. What two numbers have a sum of $- 4$ $-4$ and a product of $- 32$ $-32$ ?

After some trial and error, we arrive at $- 8$ $-8$ and $4$ $4$ . Thus, we have

$\frac{(t - 8) (t + 4)}{t - 8}$ $((t-8)(t+4))/(t-8)$

which can be simplified to

$(cancel((t-8))(t+4))/cancel(t-8)$

$=>t+4$

Hope this helps!

How do you simplify (t^2-4t-32)/(t-8)?t2−4t−32t−8?(t^2-4t-32)/(t-8)??