How do you simplify $\frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} - \sqrt{3}}$ $(sqrt7+sqrt3)/(sqrt7-sqrt3)$ ?

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How do you simplify $\frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} - \sqrt{3}}$ $(sqrt7+sqrt3)/(sqrt7-sqrt3)$ ?

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Answer 1 · 2016-08-29T08:36:48

$\frac{{(\sqrt{7} + \sqrt{3})}^{2}}{4}$ $(sqrt7+sqrt3)^2/4$

Explanation:

Multiply both sides by $\frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} + \sqrt{3}}$ $(sqrt7+sqrt3)/(sqrt7+sqrt3)$

$\frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} - \sqrt{3}} \times \frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} + \sqrt{3}}$ $(sqrt7+sqrt3)/(sqrt7-sqrt3) xx (sqrt7+sqrt3)/(sqrt7+sqrt3)$

The bottom shows the factors of the difference of squares.

$\frac{{(\sqrt{7} + \sqrt{3})}^{2}}{{\sqrt{7}}^{2} - {\sqrt{3}}^{2}} = \frac{{(\sqrt{7} + \sqrt{3})}^{2}}{7 - 3}$ $(sqrt7+sqrt3)^2/(sqrt7^2 - sqrt3^2) = (sqrt7+sqrt3)^2/(7-3)$

$\frac{{(\sqrt{7} + \sqrt{3})}^{2}}{4}$ $(sqrt7+sqrt3)^2/4$

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How do you simplify $\frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} - \sqrt{3}}$ $(sqrt7+sqrt3)/(sqrt7-sqrt3)$ ?

1 Answer

Explanation:

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How do you simplify √7+√3√7−√3(sqrt7+sqrt3)/(sqrt7-sqrt3)?

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How do you simplify $\frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} - \sqrt{3}}$ $(sqrt7+sqrt3)/(sqrt7-sqrt3)$ ?