How do you simplify #sqrt35/sqrt14#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Mar 27, 2016 #sqrt(35)/sqrt(14)= color(green)(sqrt(2.5))# Explanation: #sqrt(35)/sqrt(14)# #color(white)("XXX")=(sqrt(5)*cancel(sqrt(7)))/(sqrt(2)*cancel(sqrt(7)))# #color(white)("XXX")= sqrt(5/2)# #color(white)("XXX")=sqrt(2.5)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 930 views around the world You can reuse this answer Creative Commons License