How do you simplify $\sqrt{3} \sqrt{6} + \sqrt{3}$ $sqrt3 sqrt6 + sqrt3$ ?

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Answer 1 · 2016-08-19T10:31:50

$3 \sqrt{3}$ $3sqrt3$

We can change $\sqrt{6} \sqrt{3}$ $sqrt6sqrt3$ into $\sqrt{18}$ $sqrt18$

$\sqrt{18} = \sqrt{3 \times 3 \times 2} = 2 \sqrt{3}$ $sqrt18 = sqrt(3xx3xx2) = 2sqrt3$

Now we have $2 \sqrt{3} + 1 \sqrt{3}$ $2sqrt3 + 1 sqrt3$

= $3 \sqrt{3}$ $3sqrt3$

How do you simplify √3√6+√3sqrt3 sqrt6 + sqrt3 ?