How do you simplify #sqrt2(5+sqrt8)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Jan 5, 2017 #sqrt(2)(5+sqrt(8))=color(green)(5sqrt(2)+4)# Explanation: #sqrt(2)(5+sqrt(8))# #color(white)("XXX")=sqrt(2) * 5 + sqrt(2) * sqrt(8)# (distributive property) #color(white)("XXX")=5sqrt(2)+sqrt(16)# #color(white)("XXX")=5sqrt(2)+4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 876 views around the world You can reuse this answer Creative Commons License