How do you simplify $\sqrt{15} \cdot \sqrt{3} + \sqrt{15} \cdot 2 \sqrt{5}$ $sqrt15sqrt3+sqrt152sqrt5$ ?

Question

1140 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-16T17:20:44

$3 \sqrt{5} + 10 \sqrt{3}$ $3sqrt5 + 10sqrt3$

If square roots are being multiplied or divided they can be combined into one square root. Write the numbers as the product of prime factors.

$\sqrt{15} \times \sqrt{3} + \sqrt{15} \times 2 \sqrt{5}$ $sqrt15 xxsqrt3 + sqrt15 xx 2sqrt5$

= $\sqrt{5 \times 3 \times 3} + 2 \sqrt{3 \times 5 \times 5}$ $sqrt(5xx3xx3) + 2sqrt(3xx5xx5)$

= $3 \sqrt{5} + 2 \times 5 \sqrt{3}$ $3sqrt5 + 2xx5sqrt3$

= $3 \sqrt{5} + 10 \sqrt{3}$ $3sqrt5 + 10sqrt3$

How do you simplify sqrt15*sqrt3+sqrt15*2sqrt5√15⋅√3+√15⋅2√5sqrt15*sqrt3+sqrt15*2sqrt5?