How do you simplify $\sqrt{y + 1} - 3 = 1$ $sqrt(y + 1) -3 = 1$ ?

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Answer 1 · 2016-05-03T11:04:35

$y = 15$ $y=15$

As $\sqrt{y + 1} - 3 = 1$ $sqrt(y+1)-3=1$

$\sqrt{y + 1} - 3 + 3 = 1 + 3$ $sqrt(y+1)-3+3=1+3$

or $\sqrt{y + 1} = 4$ $sqrt(y+1)=4$

Squaring both sides

$(y + 1) = 16$ $(y+1)=16$

or $y = 16 - 1 = 15$ $y=16-1=15$

How do you simplify √y+1−3=1sqrt(y + 1) -3 = 1?