How do you simplify $\sqrt{x^{4}}$ $sqrt (x^4)$ ?

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How do you simplify $\sqrt{x^{4}}$ $sqrt (x^4)$ ?

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Answer 1 · 2016-04-04T10:11:25

$\pm x^{2}$ $+-x^2$

Explanation:

$a^{\frac{1}{N}}$ $a^(1/N)$ has N values that are the roots of $a^{N} = 1$ $a^N=1$

The roots might include complex values that occur in conjugate pairs.

Very briefly, $\sqrt{1} = \pm 1$ $sqrt1=+-1$ .
$\sqrt{x^{4}} = {(x^{4})}^{\frac{1}{2}}$ $sqrt(x^4) = (x^4)^(1/2)$ has two values $\pm x^{2}$ $+-x^2$ .
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How do you simplify $\sqrt{x^{4}}$ $sqrt (x^4)$ ?

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How do you simplify $\sqrt{x^{4}}$ $sqrt (x^4)$ ?