How do you simplify #sqrt((9x^2y)/(32z^3))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer EZ as pi Sep 6, 2016 #(3x)/(4z)sqrt(y/(2z))# Explanation: #sqrt((9x^2y)/(32z^3)) color(white)(xxxxxx)larr# find the square roots where possible. =#sqrt((3^2x^2y)/(4^2xx2z^2 z))color(white)(xxxxxx)larr# identify the squares. =#(3x)/(4z)sqrt(y/(2z))# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1183 views around the world You can reuse this answer Creative Commons License