How do you simplify #sqrt. 72 - sqrt.50#?

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Answer 1 · 2015-05-20T22:37:48

#sqrt(0.72)-sqrt(0.50)#

#=sqrt(72/100)-sqrt(50/100)#

#=sqrt(72)/sqrt(100)-sqrt(50)/sqrt(100)#

#=(sqrt(72)-sqrt(50))/10#

#=(sqrt(2xx6^2)-sqrt(2xx5^2))/10#

#=(6sqrt(2)-5sqrt(2))/10#

#=sqrt(2)/10#