How do you simplify #sqrt(45x^2) div sqrt(9)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Sep 13, 2015 #sqrt(45x^2) div sqrt(9) = sqrt(5)abs(x)# Explanation: #sqrt(45x^2)/sqrt(9# #color(white)("XXX")= sqrt(9*5*x^2)/sqrt(9)# #color(white)("XXX")=(cancel(sqrt(9))*sqrt(5)*sqrt(x^2))/cancel(sqrt(9))# #color(white)("XXX")=sqrt(5)*abs(x)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1222 views around the world You can reuse this answer Creative Commons License