# How do you simplify sqrt(16/3)?

$\setminus \frac{4 \setminus \sqrt{3}}{3}$
$\setminus \sqrt{\setminus \frac{16}{3}} = \setminus \frac{\setminus \sqrt{16}}{\setminus \sqrt{3}}$
$= \setminus \frac{4}{\sqrt{3}}$ multiply by the conjugate of the denominator:
$\setminus \frac{4}{\sqrt{3}} \cdot \setminus \frac{\sqrt{3}}{\sqrt{3}}$
$= \setminus \frac{4 \setminus \sqrt{3}}{3}$