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How do you simplify #root3(128x^6)#?

1 Answer

Sep 27, 2015

#4x^2 *2^(1/3)#

Explanation:

Written in exponent form it is #(128x^6)^(1/3)#

= #(2^7 x^6)^(1/3)#

=#2^(6/3)*2^(1/3) *x^(6/3)#

=#2^2 *2^(1/3) *x^2#

= #4x^2 *2^(1/3)#

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