How do you simplify $\frac{p^{2} - 64}{p + 8}$ $(p^2-64)/(p+8)$ ?

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Answer 1 · 2016-05-02T11:40:02

$p - 8$ $p-8$

Notice that $8 \times 8 = 64$ $8xx8=64$

Write as

$\frac{p^{2} - 8^{2}}{p + 8}$ $" "(p^2-8^2)/(p+8)$

But $p^{2} - 8^{2} = (p + 8) (p - 8)$ $p^2-8^2 = (p+8)(p-8)$

$(cancel((p+8))(p-8))/(cancel(p+8))$

$p-8$

How do you simplify (p^2-64)/(p+8)p2−64p+8(p^2-64)/(p+8)?