How do you simplify $\frac{(p + 1) {(2 p - 1)}^{4}}{{(p + 1)}^{2} {(2 p - 1)}^{2}}$ $((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$ ?

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How do you simplify $\frac{(p + 1) {(2 p - 1)}^{4}}{{(p + 1)}^{2} {(2 p - 1)}^{2}}$ $((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$ ?

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Answer 1 · 2017-04-15T20:01:02

$\frac{{(2 p - 1)}^{2}}{(p + 1)}$ $((2p-1)^2)/((p+1))$

Explanation:

This is just a question of knowing your indice laws.

$\frac{(p + 1) {(2 p - 1)}^{4}}{{(p + 1)}^{2} {(2 p - 1)}^{2}}$ $((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$

When there is a division of indices with the same base, the indices are subtracted.

For $(p + 1)$ $(p+1)$ , it is $1 - 2 = - 1$ $1-2 = -1$ , therefore the (p+1) on the numerator disappears and the one on the denominator stays.

$\frac{{(2 p - 1)}^{4}}{(p + 1) {(2 p - 1)}^{2}}$ $((2p-1)^4)/((p+1)(2p-1)^2)$

For $(2 p - 1)$ $(2p-1)$ , it is $4 - 2 = 2$ $4-2=2$ , therefore the $(2 p - 1)$ $(2p-1)$ on the denominator disappears and the one on the numerator stays.

$\frac{{(2 p - 1)}^{2}}{(p + 1)}$ $((2p-1)^2)/((p+1))$

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How do you simplify $\frac{(p + 1) {(2 p - 1)}^{4}}{{(p + 1)}^{2} {(2 p - 1)}^{2}}$ $((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$ ?

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How do you simplify (p+1)(2p−1)4(p+1)2(2p−1)2((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)?

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How do you simplify $\frac{(p + 1) {(2 p - 1)}^{4}}{{(p + 1)}^{2} {(2 p - 1)}^{2}}$ $((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$ ?