How do you simplify $\frac{n!}{(n - 3)!}$ $(n!)/((n-3)!)$ ?

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Answer 1 · 2018-03-17T08:34:43

$\frac{n!}{(n - 3)!} = n^{3} - 3 n^{2} + 2 n$ $(n!)/((n-3)!)=n^3-3n^2+2n$

$\frac{n!}{(n - 3)!}$ $(n!)/((n-3)!)$

= $(n(n-1)(n-2)color(blue)((n-3)(n-4).....3*2*1))/((n-3)(n- 4).....3*2*1)$

= $n(n-1)(n-2)$

= $n(n^2-3n+2)$

= $n^3-3n^2+2n$

How do you simplify (n!)/((n-3)!)n!(n−3)!(n!)/((n-3)!)?