How do you simplify $\frac{n!}{(n - 2)!}$ $(n!)/((n-2)!)$ ?

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Answer 1 · 2016-11-02T03:29:55

This can be simplified to $n (n - 1) = n^{2} - n$ $n(n - 1) = n^2- n$ .

Expand the factorial in the numerator, using the definition that $n! = (n)(n - 1)(n - 2)(n - 3)...$ .

$(n!)/((n - 2)!)$

$=>((n)(n - 1)(n - 2)!)/((n -2)!)$

$=>n(n - 1)$

$=>n^2- n$

Hopefully this helps!

Answer 2 · 2016-11-02T03:34:47

Please see the explanation to understand how it simplifies to $n(n -1)$

$(n!)/((n -2)!) = ((n)(n-1)(n-2)!)/((n-2)!) =$

Cancel:

$((n)(n-1)cancel(n-2)!)/(cancel(n-2)!) = n(n -1)$

How do you simplify (n!)/((n-2)!)n!(n−2)!(n!)/((n-2)!)?