How do you simplify n(n-1)!n(n1)!?

1 Answer
Oct 25, 2016

n(n-1)! =n!n(n1)!=n!

Explanation:

A number represented by a!a! (where aa is a natural number) is

axx(a-1)xx(a-2)xx....xx4xx3xx2xx1

i.e. product of all the numbers from a downwards till 1,

Hence, (n-1)! =(n-1)xx(n-2)xx(n-3)xx....xx4xx3xx2xx1

and n(n-1)! is

nxx[(n-1)xx(n-2)xx(n-3)xx....xx4xx3xx2xx1]

or nxx(n-1)xx(n-2)xx(n-3)xx....xx4xx3xx2xx1

But this is n!

Hence n(n-1)! =n!