How do you simplify $\frac{n - 5}{n^{2} - 25}$ $(n-5)/(n^2-25)$ ?

Question

1914 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-22T18:41:39

$= \frac{n - 5}{(n - 5) (n + 5)} = \frac{1}{n + 5} = {(n + 5)}^{- 1} .$ $= (n-5)/((n-5)(n+5)) = 1/(n+5) = (n+5)^-1.$

$= \frac{n - 5}{(n - 5) (n + 5)} = \frac{1}{n + 5} = {(n + 5)}^{- 1} .$ $= (n-5)/((n-5)(n+5)) = 1/(n+5) = (n+5)^-1.$

graph{(y-(x+5)^(-1))=0 [-10, 10, -5, 5]}

How do you simplify (n-5)/(n^2-25)n−5n2−25 (n-5)/(n^2-25)?