How do you simplify $((n+3)!)/(n!)$ ?

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Answer 1 · 2015-11-11T18:00:49

$n^3+6n^2 +11n +6$

$((n+3)(n+2)(n+1)n!)/(n!)$

$(n+3)(n+2)(n+1) times (n!)/(n!)$

$(n+3)(n+2)(n+1)$

$(n+3)(n^2+3n+2)$

$n^3+3n^2+2n +3n^2+9n+6$

$n^3+6n^2 +11n +6$

How do you simplify ((n+3)!)/(n!)((n+3)!)/(n!)?