How do you simplify ((n-1)!) /( n!) (n1)!n!?

1 Answer
Dec 3, 2015

Answer: 1/n1n

Explanation:

Factorial mean multiply the all the number by counting down...

((n-1)!)/(n!) = [(n-1)(n-2)(n-3)!]/((n)(n-1)(n-2)(n-3)!(n1)!n!=(n1)(n2)(n3)!(n)(n1)(n2)(n3)!

= [cancel((n-1)(n-2)(n-3)!)]/((n)cancel((n-1)(n-2)(n-3)!)

= 1/n