How do you simplify $log_2(2^x)$ ?

Question

7696 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-15T12:49:58

$log_2(2^x) = x$

The logarithm $log_b$ for any (meaningful) base $b$ is the inverse of the exponent using that base.

So $log_b(b^x) = x$ for any Real number $x$ and base $b > 0$ with $b != 1$

How do you simplify log_2(2^x)log_2(2^x)?