How do you simplify #log_2(2^x)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer George C. Aug 15, 2016 #log_2(2^x) = x# Explanation: The logarithm #log_b# for any (meaningful) base #b# is the inverse of the exponent using that base. So #log_b(b^x) = x# for any Real number #x# and base #b > 0# with #b != 1# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 7067 views around the world You can reuse this answer Creative Commons License