How do you simplify $Log_(2)(10)$ ?

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Answer 1 · 2015-08-30T07:30:24

$log_2(10) = 1/log(2)$

Use the change of base formula: $log_a(b) = log_c(b)/log_a(b)$

$log_2(10) = log_10(10)/log_10(2) = 1/log(2)$

since $log_10 = log$

In general, $log_a(b) = log_b(b)/log_b(a) = 1/log_b(a)$

How do you simplify Log_(2)(10)Log_(2)(10)?