How do you simplify #abs(11-pi)#? Algebra Linear Inequalities and Absolute Value Absolute Value 1 Answer Alan P. Jul 9, 2016 #abs(11-pi) = color(blue)(11-pi)# or, approximately, #color(blue)(7.85841)# Explanation: #pi# is just a number which is less than #11# So #color(white)("XXX")11-pi > 0# and #color(white)("XXX")abs(11-pi) = 11-pi# Using the approximation #pi=3.14159# #color(white)("XXX")11-pi=7.85841# Answer link Related questions How do you find absolute value of a number? What does absolute value mean? What is the absolute value of 0? What is the absolute value notation? Why are absolute values is important? How do you find the distance between 9 and -12 using absolute values? What is #-|-12|#? What is the absolute value #|\frac{1}{10}|#? What is the value of #2^(-|-2|)#? How do you write an absolute value equation that could be used to express the distance from... See all questions in Absolute Value Impact of this question 1246 views around the world You can reuse this answer Creative Commons License