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How do you simplify #(a^2-9)/a^2 * (a^2-3a)/(a^2+a-12)#?

1 Answer

Jul 19, 2015

You first factorise, and then see if you can cancel.

Explanation:

#=((a+3)(a-3))/(a*a)# #*(a(a-3))/((a-3)(a+4))#

#=(a(a+3)(a-3)(a-3))/(a*a(a-3)(a+4))#

#=(cancela(a+3)cancel((a-3))(a-3))/(cancela*acancel((a-3))(a+4))#

#=(a^2-9)/(a^2+4a)#

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