How do you simplify (9sqrt25)/sqrt509√25√50?

3 Answers
Zach · EZ as pi
Apr 27, 2018

9/sqrt29√2

Explanation:

(9 sqrt25)/sqrt509√25√50

= (9xx5)/sqrt 50=9×5√50

sqrt50√50 can be simplified to sqrt(25xx2) = 5sqrt 2√25×2=5√2

45 /( 5 sqrt 2)455√2

= 9 /sqrt29√2

Mark D.
Apr 27, 2018

[9sqrt2]/29√22

Explanation:

9sqrt259√25 = 9 xx 59×5 = 45

sqrt50=sqrt25xx2=5sqrt2√50=√25×2=5√2

so [9sqrt25]/sqrt50=45/[5sqrt2]9√25√50=455√2

dividing by top and bottom by 5 leaves

9/sqrt29√2

If we multiply top and bottom by sqrt2√2 this will rationalise it (remove the surd from the denominator)

9/sqrt2 xx sqrt2/sqrt29√2×√2√2 =[9sqrt2]/29√22

Jobless · EZ as pi
Apr 27, 2018

(9sqrt25)/sqrt50 = (9sqrt2)/29√25√50=9√22

Explanation:

sqrt(ab) = sqrta *sqrtb√ab=√a⋅√b

So, (9sqrt25)/sqrt50 =(9sqrt25)/(sqrt25*sqrt2 )=9/sqrt29√25√50=9√25√25⋅√2=9√2

9/sqrt2 xx sqrt2/sqrt2 = (9sqrt2)/29√2×√2√2=9√22

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