How do you simplify $9^(log_9x)$ ?

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Answer 1 · 2016-08-22T22:09:25

$9^(log_9 x)=x$

Let $9^(log_9 x)=u$ , then as $a^n=b$ means $log_a b=n$ , we have

$log_9 u=log_9 x$ .

Hence $u=x$ and $9^(log_9 x)=x$

How do you simplify 9^(log_9x)9^(log_9x)?