How do you simplify #9^(log_9x)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Aug 22, 2016 #9^(log_9 x)=x# Explanation: Let #9^(log_9 x)=u#, then as #a^n=b# means #log_a b=n#, we have #log_9 u=log_9 x#. Hence #u=x# and #9^(log_9 x)=x# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 2060 views around the world You can reuse this answer Creative Commons License