How do you simplify $8 z (2 z^{2} - 15)$ $8z(2z^2-15)$ ?

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Answer 1 · 2018-05-21T17:48:17

$16 z^{3} - 120 z$ $16z^3-120z$

I assume since this is a distributive property question:

$8 z (2 z^{2} - 15)$ $8z(2z^2-15)$

$16 z^{3} - 120 z$ $16z^3-120z$

Whether that form is simpler or not remains to be debated :-)

How do you simplify 8z(2z^2-15)8z(2z2−15)8z(2z^2-15)?