How do you simplify $(8x^5-10xy^2)/(2xy^2)$ and what are the excluded values of the variables?

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Answer 1 · 2017-04-18T06:45:26

$=(4x^4-5y^2)/y^2" or "=(4x^4)/y^2 -5$

$xand y$ may not be $0$

The excluded values are any values that would make the denominator equal to $0$ , or any number that we use to divide.
$xand y$ may not be $0$

$(8x^5 -10xy^2)/(2xy^2)" "larr$ factorise the numerator

$=(2x(4x^4-5y^2))/(2xy^2)$

$=(cancel(2x)(4x^4-5y^2))/(cancel(2x)y^2)$

$=(4x^4-5y^2)/y^2$

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You could also split the fraction into two separate fractions:

$(8x^5)/(2xy^2) -(10xy^2)/(2xy^2)$

$=(4x^4)/y^2 -5$

This leaves two terms in the answer.

How do you simplify (8x^5-10xy^2)/(2xy^2)(8x^5-10xy^2)/(2xy^2) and what are the excluded values of the variables?