How do you simplify #(7x^2yz)^3#?

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Answer 1 · 2017-07-18T08:46:09

#=343x^6y^3z^3#

The index shown applies to all the factors inside the bracket.

Recall the laws of indices:

#(xyz)^m = x^my^mz^m" and "(x^m)^n = x^(mn)#

Using both of these laws gives:

#(7x^2yz)^3 = 7^3x^6y^3z^3#

While #7^3# is acceptable, you might want to find the actual value.

#7^3x^6y^3z^3#

#=343x^6y^3z^3#