How do you simplify #(7w^11z^6)/(14w^3z^3)#?

1 Answer
smendyka
Jun 27, 2017

See a solution process below:

Explanation:

First, rewrite the expression as:

#(7/14)(w^11/w^3)(z^6/z^3) => 1/2(w^11/w^3)(z^6/z^3)#

Now, use this rule of exponents to simplify the #w# and #z# terms:

#x^color(red)(a)/x^color(blue)(b) = x^(color(red)(a)-color(blue)(b))#

#1/2(w^color(red)(11)/w^color(blue)(3))(z^color(red)(6)/z^color(blue)(3)) => 1/2(w^(color(red)(11)-color(blue)(3)))(z^(color(red)(6)-color(blue)(3))) =>#

#(w^8z^3)/2#

Related questions
See all questions in Exponential Properties Involving Quotients
Impact of this question
1456 views around the world
You can reuse this answer
Creative Commons License