How do you simplify #(6f^-2 g^3 h^5 )/(54f^-2 g^-5 h^3)#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Mark D. · CountryGirl May 29, 2018 #(g^8h^2)/9# Explanation: Simplify all like terms: #6/54=1/9# #f^-2/(f^-2)=f^(-2- -2)=f^(-2+2)=f^0=1# #g^3/(g^-5)=g^(3- -5)= g^(3 + 5) = g^8# #h^5/h^3=h^(5-3)=h^2# Put these together: #(g^8h^2)/9# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 2384 views around the world You can reuse this answer Creative Commons License