How do you simplify ${(\frac{6}{z^{4}})}^{3}$ $(6/z^4)^3$ and write it using only positive exponents?

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Answer 1 · 2016-09-01T15:07:35

$\frac{216}{z^{12}}$ $216/z^12$

You have cube everything in the bracket.
(multiply it by itself any by itself again.)

${(\frac{6}{z^{4}})}^{3} = \frac{6^{3}}{z^{4 \times 3}}$ $(6/z^4)^3 = 6^3/z^(4xx3)$

= $\frac{216}{z^{12}}$ $216/z^12$

How do you simplify (6z4)3(6/z^4)^3 and write it using only positive exponents?