How do you simplify # (-6 + sqrt99) /15#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Sep 7, 2017 #(-6+sqrt(99))/15=color(red)((-2+sqrt(11))/5)# Explanation: #(-6+sqrt(99))/15# #color(white)("XXX")=(-3 * 2+ sqrt(9) * sqrt(11))/(3 * 5)# #color(white)("XXX")=(-3 * 2 + 3 * sqrt(11))/(3 * 5)# #color(white)("XXX")=(cancel(3) * (-2+sqrt(11)))/(cancel(3) * 5)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 951 views around the world You can reuse this answer Creative Commons License