How do you simplify $(6+sqrt128)/2$ ?

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Answer 1 · 2015-07-10T17:04:04

$=color(blue)(3 +sqrt32)$

$sqrt128 = color(green)(sqrt(4 * 32)$
The expression can be written as:

$((6+ color(green)(sqrt(4 * 32)))/2)$

$=((6+ 2(sqrt 32))/2)$

$2$ is common to both terms of the numerator:

$=cancel2((3+ (sqrt( 32)))/cancel2)$

$=color(blue)(3 +sqrt32)$

How do you simplify (6+sqrt128)/2(6+sqrt128)/2?