How do you simplify #5^(log_5x)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Cesareo R. Feb 13, 2017 See below. Explanation: Make #y = 5^(log_5x)# Apply #log_5# to both sides #log_5y=log_5xlog_5 5=log_5x cdot 1=log_5 x# Now #log_5y=log_5x->y=x# so #5^(log_5x)=x# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 8759 views around the world You can reuse this answer Creative Commons License