How do you simplify #5 ln (1/e^2)#?

1 Answer
Alan P.
Apr 20, 2016

#5ln(1/(e^2))=color(green)(-10)#

Explanation:

Remember: #ln a = k# is equivalent to #e^k=a#

Considering #ln(1/(e^2))=k#
#color(white)("XXX")a=1/(e^2)=e^(-2)#
so
#color(white)("XXX")k=-2#

If #ln (1/(e^2))=-2#
then
#color(white)("XXX")5ln(1/(e^2))=5xx(-2)=-10#

Related questions
See all questions in Common Logs
Impact of this question
1482 views around the world
You can reuse this answer
Creative Commons License