How do you simplify $(4xy^3)/(x^2y)*y/(8x)$ ?

Question

4300 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-12T11:43:08

Multiply and divide out common factors

$(4xy^3) /(x^2y) xx y/(8x) = (4 x y^4)/(8x^3 y^1)$

The common factors are 4xy Divide both the numerator and the denominator by the the common factors of 4xy

$(4xy^4)/(4xy) = y^3$

$(8 x^3y^1)/(4xy)= 2x^2$

So the simplified version of the fraction is

$y^3/(2x^2)$

How do you simplify (4xy^3)/(x^2y)*y/(8x)(4xy^3)/(x^2y)*y/(8x)?