How do you simplify $4 \sqrt{8} \cdot \sqrt{2}$ $4sqrt8*sqrt2$ ?

Question

How do you simplify $4 \sqrt{8} \cdot \sqrt{2}$ $4sqrt8*sqrt2$ ?

2 Answers

Impact of this question

2104 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-07T02:56:09

1) $4 \sqrt{4 \times 2} \cdot \sqrt{2}$ $4sqrt(4xx2)*sqrt2$

2) $(4 \sqrt{4} \cdot \sqrt{2}$ $(4sqrt4*sqrt2$ ) ⋅ $\sqrt{2}$ $sqrt2$

3) $4 \times 2 \sqrt{2} \cdot \sqrt{2}$ $4xx2sqrt2*sqrt2$

4) $8 \cdot 2$ $8*2$

5) $16$ $16$

Explanation:

1) Find factors of $8$ $8$ under the radical.
2) Simplify $\sqrt{4}$ $sqrt4$ to $2$ $2$ and multiply by the $4$ $4$ outside
3) Multiply $8 \sqrt{2} \cdot \sqrt{2} (\leftarrow \sqrt{2} \cdot \sqrt{2}$ $8sqrt2*sqrt2" "(larrsqrt2*sqrt2$ equals 2)
4) $8 \cdot 2$ $8*2$
5) $16$ $16$

Answer 2 · 2017-09-07T05:39:21

$= 16$ $=16$

Explanation:

The two square roots can be combined into one. In this case this is a good idea because the product will be a prefect square.

$4 \sqrt{8} \times \sqrt{2} = 4 \sqrt{8 \times 2}$ $4sqrt8 xx sqrt2 = 4sqrt(8xx2)$

$= 4 \sqrt{16}$ $= 4 sqrt(16)$

$= 4 \times 4$ $= 4xx4$

$= 16$ $=16$

Science

Math

Humanities

... and beyond

How do you simplify $4 \sqrt{8} \cdot \sqrt{2}$ $4sqrt8*sqrt2$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify 4√8⋅√24sqrt8*sqrt2?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you simplify $4 \sqrt{8} \cdot \sqrt{2}$ $4sqrt8*sqrt2$ ?